js数组排序处理
如何根据给定的物品数量，对带有价格和物品名称的数组进行排序，使其以物品名称和价格为准进行竖向排列？
问题详述：
给定数组：
let arr = [ {price: 5, useruid: 0, item_name: '测试3'}, {price: 20, useruid: 0, item_name: '测试2'}, {price: 23, useruid: 0, item_name: '测试1'}, {price: 39, useruid: 0, item_name: '测试2'}, {price: 43, useruid: 0, item_name: '测试1'}, {price: 55, useruid: 0, item_name: '测试3'}, {price: 66, useruid: 0, item_name: '测试2'}, {price: 72, useruid: 0, item_name: '测试3'}, {price: 82, useruid: 0, item_name: '测试3'}, {price: 97, useruid: 0, item_name: '测试3'}, ]
let items = [ { id: 1, num: 2 } { id: 2, num: 3 } { id: 3, num: 5 } ]
期望输出：
let result= [ [{price: 5, useruid: 0, item_name: '测试3'},{price: 39, useruid: 0, item_name: '测试2'},] [{price: 20, useruid: 0, item_name: '测试2'},{price: 43, useruid: 0, item_name: '测试1'},{price: 66, useruid: 0, item_name: '测试2'},] [{price: 23, useruid: 0, item_name: '测试1'},{price: 55, useruid: 0, item_name: '测试3'},{price: 72, useruid: 0, item_name: '测试3'},{price: 82, useruid: 0, item_name: '测试3'},{price: 97, useruid: 0, item_name: '测试3'},]]
解决方案：
const result: (typeof arr)[0][][] = new array(items.length) .fill(0) .map(() => [])for (let flag = true, index = 0; flag; ) { flag = false items.foreach((v, i) => { const a = result[i] if (a.length < v.num) { a.push(arr[index++]) flag = true } })}console.log(result)
输出：
[ [ { price: 5, userUid: 0, item_name: "测试3" }, { price: 39, userUid: 0, item_name: "测试2" } ], [ { price: 20, userUid: 0, item_name: "测试2" }, { price: 43, userUid: 0, item_name: "测试1" }, { price: 66, userUid: 0, item_name: "测试2" } ], [ { price: 23, userUid: 0, item_name: "测试1" }, { price: 55, userUid: 0, item_name: "测试3" }, { price: 72, userUid: 0, item_name: "测试3" }, { price: 82, userUid: 0, item_name: "测试3" }, { price: 97, userUid: 0, item_name: "测试3" } ]]
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