为快捷显示Oracle执行计划创建存储过程 第一种:不设置输出格式参数,即用默认的 SQLgt; create or replace procedure sql_expl
为快捷显示oracle执行计划创建存储过程
第一种:不设置输出格式参数,,即用默认的
SQL> create or replace procedure sql_explain(v_sql varchar2)
2 is
3 type explain_cursor_type is ref cursor;
4 explain_cursor explain_cursor_type;
5 a varchar2(2048);
6 begin
7 execute immediate ‘explain plan for ‘||v_sql;
8 open explain_cursor for select PLAN_TABLE_OUTPUT from table(dbms_xplan.display());
9 loop
10 fetch explain_cursor into a;
11 exit when explain_cursor%NOTFOUND;
12 dbms_output.put_line(a);
13 end loop;
14 end;
15 /
Procedure created.
SQL> exec sql_explain(‘select a.name,b.name from t1 a,t2 b where a.id=b.id and a.id=1’);
Plan hash value: 2680223496
————————————————————————————–
| Id | Operation | Name | Rows | Bytes | Cost (%CPU)| Time |
————————————————————————————–
| 0 | SELECT STATEMENT | | 1 | 17 | 4 (0)| 00:00:01 |
| 1 | NESTED LOOPS | | 1 | 17 | 4 (0)| 00:00:01 |
| 2 | TABLE ACCESS BY INDEX ROWID| T1 | 1 | 8 | 1 (0)| 00:00:01 |
|* 3 | INDEX UNIQUE SCAN | T1_PK | 1 | | 0 (0)| 00:00:01 |
|* 4 | TABLE ACCESS FULL | T2 | 1 | 9 | 3 (0)| 00:00:01 |
————————————————————————————–
Predicate Information (identified by operation id):
—————————————————
3 – access(“A”.”ID”=1)
4 – filter(“B”.”ID”=1)
PL/SQL procedure successfully completed.
SQL> exec sql_explain(‘select a.name,b.name from t1 a,t2 b where a.id=b.id and a.id=”1”’);
Plan hash value: 2680223496
————————————————————————————–
| Id | Operation | Name | Rows | Bytes | Cost (%CPU)| Time |
————————————————————————————–
| 0 | SELECT STATEMENT | | 1 | 17 | 4 (0)| 00:00:01 |
| 1 | NESTED LOOPS | | 1 | 17 | 4 (0)| 00:00:01 |
| 2 | TABLE ACCESS BY INDEX ROWID| T1 | 1 | 8 | 1 (0)| 00:00:01 |
|* 3 | INDEX UNIQUE SCAN | T1_PK | 1 | | 0 (0)| 00:00:01 |
|* 4 | TABLE ACCESS FULL | T2 | 1 | 9 | 3 (0)| 00:00:01 |
————————————————————————————–
Predicate Information (identified by operation id):
—————————————————
3 – access(“A”.”ID”=1)
4 – filter(“B”.”ID”=1)
PL/SQL procedure successfully completed.

版权声明:本文内容由互联网用户自发贡献,该文观点仅代表作者本人。本站仅提供信息存储空间服务,不拥有所有权,不承担相关法律责任。
如发现本站有涉嫌抄袭侵权/违法违规的内容, 请发送邮件至 chuangxiangniao@163.com 举报,一经查实,本站将立刻删除。
发布者:程序猿,转转请注明出处:https://www.chuangxiangniao.com/p/558591.html
微信扫一扫
支付宝扫一扫