获取表有多少行
技巧:
select count(*) from table_name;
取出cat_id=4和cat_id=11的列
使用or select * from goods where cat_id=4 or cat_id=11;
不使用or select * from goods where cat_id in(4,11);
取出价格>=100 且<=500
select * from goods where shop_price >= 100 and shop_price <= 500;select * from goods where shop_price between 100 and 500;
取出价格=500
select * from goods where shop_price = 500;select * from goods where shop_price not between 100 and 500;
in是散点的集合,between and是区间
cat_id不是3也不是11的列
select * from goods where cat_id!=3 and cat_id!=11;select * from goods where cat_id not in(3,11);
算出比市场价优惠的数值
select goods_id,(market_price-shop_price) as chajia ,goods_name from goods ;
查找本地价格比市场价便宜200以上的
select goods_id,(market_price-shop_price) as chajia ,goods_name from goods where (market_price - shop_price) > 200;
(chajia列是where作用过之后的产生的)
疑点注意:where是对真实表中的数据发挥作用,having可以对where结果进行过滤
select goods_id,(market_price-shop_price) as chajia ,goods_name from goods where chajia > 200;(错误的)
作用相同
企奶奶
一款专注于企业信息查询的智能大模型,企奶奶查企业,像聊天一样简单。
56 查看详情
select goods_id,(market_price-shop_price) as chajia ,goods_name from goods having chajia>200;
把mian表中的num列中 [20,29]改为20 [30,39]改为30
update mian set num = floor(num/10)*10 where num between 20 and 39;
like模糊查询
截取诺基亚后面的内容
select goods_id ,goods_name,substring(goods_name,4) from goods where goods_name like '诺基亚%';
查找有诺基亚开头的更换为htc(没有更改真实表内容)
select goods_id ,goods_name,concat('htc',substring(goods_name,4)) from goods where goods_name like '诺基亚%';
把诺基亚更换为htc(更改真实表内容)
update goods set goods_name = concat('htc',substring(goods_name,4))where goods_name like '诺基亚%' and cat_id=4;
以上就是mysql 查的内容,更多相关内容请关注PHP中文网(www.php.cn)!
版权声明:本文内容由互联网用户自发贡献,该文观点仅代表作者本人。本站仅提供信息存储空间服务,不拥有所有权,不承担相关法律责任。
如发现本站有涉嫌抄袭侵权/违法违规的内容, 请发送邮件至 chuangxiangniao@163.com 举报,一经查实,本站将立刻删除。
发布者:程序猿,转转请注明出处:https://www.chuangxiangniao.com/p/802668.html
微信扫一扫
支付宝扫一扫